Airline Schedule Probability Calculation

What is the probability that the first two flights are on schedule and the third one is not on schedule? The probability of the first two flights being on schedule and the third one not being on schedule can be calculated using the given information. The probability of a flight being on schedule is 0.9 and the probability of a flight not being on schedule is 0.1. Since three flights are selected at random, the total number of flights is 3. Therefore, the probability can be calculated as follows: P(first two are on schedule and the third one is not on schedule) = P(on schedule) * P(on schedule) * P(not on schedule) P(first two are on schedule and the third one is not on schedule) = 0.9 * 0.9 * 0.1 P(first two are on schedule and the third one is not on schedule) = 0.081 or 8.1%

To calculate the probability of the first two flights being on schedule and the third one not being on schedule, we use the formula for the multiplication of probabilities. This formula states that the probability of two or more independent events occurring simultaneously is equal to the product of their individual probabilities.

In this case, the probability of the first flight being on schedule is 0.9, the probability of the second flight being on schedule is also 0.9, and the probability of the third flight not being on schedule is 0.1. By multiplying these probabilities together, we get 0.081 or 8.1%.

Therefore, the probability that the first two flights are on schedule and the third one is not on schedule is 8.1%. This means that out of all the possible combinations of three flights, approximately 8.1% of them will have the first two flights on schedule and the third one not on schedule.

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