Ampasanya adalah 6.00 M
Molarity Calculation of HCl Solution
A 1.00 L volume of HCl reacted completely with 2.00 L of 1.50 M Ca(OH)2 according to the balanced chemical equation below.
2HCl + Ca(OH)2 → CaCl2 + 2H2O
What was the molarity of the HCl solution?
A. 0.375 M
B. 1.50 M
C. 3.00 M
D. 6.00 M
The answer is D
The molarity of the HCl solution is 6.00 M
Calculation:
2HCl + Ca(OH)2 → CaCl2 + 2H2O
Step 1: Find the moles of Ca(OH)2
= molarity x volume
= 2 L x 1.5 mol/L = 3.00 moles
Step 2: Use the mole ratio of HCl : Ca(OH)2 to calculate the moles of HCl
That is Ca(OH)2 : HCl is 2:1 therefore the moles of HCl = 3.00 moles x 2 = 6.00 moles
Step 3: Find the molarity of HCl
Molarity of HCl = moles of HCl / volume in liters of HCl
= 6.00 moles / 1 L = 6.00 M
What was the molarity of the HCl solution? The molarity of the HCl solution is 6.00 M.