Chemical Reaction Stoichiometry: How Many Grams of HCl are Required?

How many grams of HCl would be required to produce 6.3 x 10¹² molecules of hydrogen using the given reaction?

Find the mass of HCl needed to produce the same number of H2 molecules according to the provided reaction.

Answer:

Approximately 3.7 nanograms of HCl are required to produce 6.3 x 10¹² molecules of hydrogen.

Explanation:

The problem involves understanding the stoichiometry of a chemical reaction. The given reaction is: HCl + Na -> NaCl + H2. From the reaction, it is evident that 1 molecule of HCl produces 1 molecule of H2. Therefore, to produce 6.3 x 10¹² molecules of H2, we need 6.3 x 10¹² molecules of HCl.

To convert molecules to grams, we use the molar mass of HCl, which is approximately 36.5 g/mol. Since 1 mole contains about 6.022 x 10²³ molecules (Avogadro's number), we convert the number of molecules to moles and then to grams.

Setting up the conversion factor: HCl molecules -> moles -> grams

Calculation: 6.3 x 10¹² molecules * (1 mol / 6.022 x 10²³ molecules) * (36.5 g / 1 mol) = 3.7 x 10^-9 g or 3.7 nanograms of HCl.

By understanding the stoichiometry of the reaction and applying conversion factors, we can determine the mass of HCl needed with precision.