How many moles of AlCl3 are there in 1.81 x 10^14 molecules of AlCl3 ?
Calculation of Moles of AlCl3
Given:
Number of molecules of AlCl3 = 1.81 x 10^14
Molar mass of AlCl3 = 133.34 g/mol
Calculation:
Number of moles = Number of molecules / Avogadro's number
Number of moles = 1.81 x 10^14 / 6.022 Ã 10^23
Number of moles â 0.3 x 10^-9 moles
Therefore, there are approximately 0.3 x 10^-9 moles of AlCl3 in 1.81 x 10^14 molecules of AlCl3.