How many moles of copper must react to form 3.50 mol of Ag?

What is the balanced chemical equation for the reaction of copper and silver nitrate?

How can we calculate the number of moles of copper needed to form 3.50 mol of silver?

Answer:

1.75 moles of copper must react to form 3.50 mol of Ag.

The balanced chemical equation for the reaction of copper (Cu) and silver nitrate (AgNO3) is:

Cu + 2AgNO3 = 2Ag + Cu(NO3)2

To calculate the number of moles of copper needed to form 3.50 mol of silver, we can use the stoichiometry of the reaction.

We know that 1 mole of copper produces 2 moles of silver based on the balanced equation.

Therefore, to form 3.50 mol of silver, we would need:

3.50 mol Ag x (1 mol Cu / 2 mol Ag) = 1.75 mol Cu

So, 1.75 moles of copper must react to form 3.50 mol of silver.