How to Calculate the Number of Ions in Aluminum Nitrate?

What is the process to calculate the number of ions in 15.6 g of aluminum nitrate?

Curious to know how to determine the number of ions in a specific amount of aluminum nitrate?

Answer:

In order to calculate the number of ions in 15.6 g of aluminum nitrate, you need to follow these steps:

  1. Find the molar mass of aluminum nitrate (Al(NO3)3).
  2. Convert the given mass of aluminum nitrate to moles using the molar mass.
  3. Multiply the number of moles by the number of ions per formula unit.

When it comes to determining the number of ions in a specific amount of aluminum nitrate, it's essential to follow a systematic approach. In this case, we are dealing with 15.6 g of aluminum nitrate. To calculate the number of ions present in this quantity, we first need to find the molar mass of aluminum nitrate, which consists of one aluminum ion (Al3+) and three nitrate ions (NO3-) per formula unit.

Let's break down the process into three key steps:

Step 1: Finding the Molar Mass of Aluminum Nitrate (Al(NO3)3)

The molar mass of aluminum nitrate can be calculated by adding the individual molar masses of aluminum (Al) and nitrate (NO3-).

  • Aluminum (Al) has a molar mass of 26.98 g/mol.
  • Nitrate (NO3-) has a molar mass of 62.01 g/mol.

Therefore, the molar mass of Al(NO3)3 is:

Molar mass of Al(NO3)3 = (1 x molar mass of Al) + (3 x molar mass of NO3-)

Molar mass of Al(NO3)3 = (1 x 26.98 g/mol) + (3 x 62.01 g/mol) = 213.0 g/mol

Step 2: Converting the Given Mass to Moles

Next, we need to convert the given mass of aluminum nitrate (15.6 g) to moles using the molar mass calculated in the previous step.

Number of moles = Given mass / Molar mass

Number of moles = 15.6 g / 213.0 g/mol = 0.0732 mol

Step 3: Determining the Number of Ions

Finally, to find the total number of ions in 15.6 g of aluminum nitrate, we multiply the number of moles by the number of ions per formula unit.

Number of ions = Number of moles x Number of ions per formula unit

Since there is one aluminum ion (Al3+) and three nitrate ions (NO3-) per formula unit, the total number of ions is:

Number of ions = 0.0732 mol x (1 + 3) = 0.2928 mol

Therefore, there are approximately 0.2928 mol of ions in 15.6 g of aluminum nitrate.

By following these steps, you can accurately determine the number of ions present in a given amount of aluminum nitrate.

← Volume calculation of copper ii nitrate solution Calculating mole fraction of sucrose in a solution →

More Posts: