The Concentration of Cl- Ions in BaCl2 Solution

What is the concentration of Cl- ions in a 375 ppm BaCl2 solution?

Answer:

The concentration of Cl- ions in the 375 ppm BaCl2 solution is 78.1 ppm.

When preparing a 375 ppm BaCl2 solution, it is essential to determine the concentration of Cl- ions in the solution. This value is crucial for various applications where knowing the specific ion concentration is required.

To find the concentration of Cl- ions in a BaCl2 solution, we need to consider the molar mass of BaCl2 and the dissociation of ions in the solution. Each formula unit of BaCl2 dissociates into one Ba²⁺ ion and two Cl⁻ ions. Therefore, for every molecule of BaCl2, we have two Cl- ions in the solution.

Given that the BaCl2 solution is 375 ppm, we can calculate the concentration of Cl- ions as follows:

First, we need to determine the molar mass of BaCl2, which is 208.26 g/mol. Then, we can use the formula

Molarity (M) = ppm x molar mass / 1000

Substituting the values, we get:

M = 375 x 208.26 / 1000 = 78.1 ppm

Therefore, the concentration of Cl- ions in the BaCl2 solution is 78.1 ppm. This value indicates the ppm of Cl- ions present in the solution, considering the dissociation of BaCl2 into two Cl- ions per molecule.

Understanding the concentration of ions in a solution is vital for various fields, including chemistry, biology, and environmental science. By accurately determining the concentration of specific ions, researchers and scientists can assess the behavior and interactions of substances in different environments.