A 3 Billiard Ball Collides with a Cue Ball
Explanation:
Given data:
- Mass of 3 billiard ball (m1) = 0.16 kg
- Initial velocity of the 3 billiard ball (U1) = 4.0 m/s
- Mass of the cue ball (m2) = 0.17 kg
- Initial velocity of the cue ball (U2) = 0 m/s
We are required to find the final velocities of both the cue ball and the 3 billiard ball after the collision.
Principle of conservation of linear momentum:
Total momenta before collision = total momenta after collision
M1U1 + M2U2 = (M1 + M2)V
Substitute the given values into the equation:
0.16*4.0 + 0.17*0 = (0.16 + 0.17)V
0.64 + 0 = 0.33V
V = 0.64/0.33 = 1.9394 m/s
Therefore, the final velocities of both the cue ball and 3 billiard ball after the collision are 1.9394 m/s.