A Car Accelerates Uniformly to Reach a Speed of 21 m/s
A car starts from rest and accelerates uniformly to reach a speed of 21m/s in 7.0 seconds
To find the acceleration of the object, we can use the formula:
A = (V - U) / t
Where:
A = acceleration
V = final velocity (21 m/s)
U = initial velocity (0 m/s since the car starts from rest)
t = time taken (7.0 seconds)
Plugging in the values:
A = (21 - 0) / 7
A = 21 / 7
A = 3 m/s^2
Therefore, the acceleration of the object is 3 m/s^2.
Working
It is given that:
Initial speed of the object, u = 0
Final speed of the object, v = 21 m/s
Time taken, t = 7 s
Using the equation of kinematics:
v = u + a × t
v = a × t
a = v / t
Substitute the values:
a = 21 m/s / 7 s
a = 3 m/s^2
So, the acceleration of the object is 3 m/s^2. This is the solution to the problem.
A car starts from rest and accelerates uniformly to reach a speed of 21m/s in 7.0 seconds. What was the acceleration of the object? Acceleration of the object is 3 m/s/s.