Acceleration and Velocity Calculation
What is the acceleration rate of a car that starts from rest and accelerates uniformly for 15 seconds?
(a) The acceleration rate of the car is 2 m/s^2.
What is the final velocity and distance traveled by the car after 15 seconds of uniform acceleration?
(a) The final velocity of the car is 30 m/s.
(b) The distance traveled by the car is 225 meters.
Answer:
The acceleration rate of the car that starts from rest and accelerates uniformly for 15 seconds is 2 m/s^2. The final velocity of the car after 15 seconds is 30 m/s, and the distance traveled by the car in this time is 225 meters.
Explanation:
In this scenario, the car undergoes uniform acceleration, which means the acceleration rate remains constant. We can use the equations of motion to calculate the final velocity and distance traveled by the car.
(a) The final velocity (v) of the car can be calculated using the formula v = u + at, where v is the final velocity, u is the initial velocity (0 in this case), a is the acceleration rate, and t is the time. Plugging in the values, we get v = 0 + (2 m/s^2 * 15 s) = 30 m/s.
(b) The distance traveled (s) by the car can be calculated using the formula s = ut + 0.5*a*t^2. Since the car starts from rest, the initial velocity u is 0. Plugging in the values, we get s = 0 + 0.5 * (2 m/s^2) * (15 s)^2 = 225 meters.