Acceleration of Wagon Calculation

What is the mass of the wagon being accelerated by two horses, Thunder and Misty, with certain forces?

Thunder is pulling with a force of 1,000 N, while Misty is pulling with a force of 800 N. The force of friction is 75 N. The acceleration of the wagon is 1.3 m/s^2. Given that the force of gravity and the normal force cancel each other out, what is the mass of the wagon?

Answer:

The mass of the wagon is approximately 1327 kg.

Explanation: In this scenario, we are dealing with the acceleration of a wagon being pulled by two horses, Thunder and Misty. Thunder exerts a force of 1,000 N, while Misty exerts a force of 800 N. The force of friction opposing the motion is 75 N.

Given that the acceleration of the wagon is 1.3 m/s^2, we can calculate the net force acting on the wagon by summing up the forces. The net force formula is:

[tex]\sum F = ma[/tex]

Where [tex]\sum F[/tex] is the net force, m is the mass of the wagon, and a is the acceleration. By summing up the forces acting on the wagon, we get:

[tex]\sum F = 1,000 N + 800 N - 75 N = 1,725 N[/tex]

Since the force of gravity and the normal force cancel each other out vertically, we only consider the horizontal forces for acceleration. By using Newton's second law, we relate the net force to the mass and acceleration of the wagon:

[tex]m = \frac{\sum F}{a} = \frac{1,725 N}{1.3 m/s^2} = 1327 kg[/tex]

Therefore, the mass of the wagon being accelerated by Thunder and Misty is approximately 1327 kg.