An Interesting Physics Problem: Net Force on a Diver

What is the net force on the diver as he is brought to rest?

The acceleration is 0, this means there is no net force acting on the diver as he comes to rest. The net force is equal to zero.

Calculation of Net Force on the Diver:

To determine the net force on the diver, we can use the equation of motion:

(Final velocity)² = (Initial velocity)² + 2 × acceleration × distance

The initial velocity is 0 since the diver is at rest on the diving board. The final velocity is also 0 since the diver comes to rest in the water. The distance fallen is 3.0 m.

We can solve for the acceleration using the given time:

0 = 0² + 2 × acceleration × 3.0

0 = 0 + 6.0 × acceleration

acceleration = 0 m/s²

Calculation for the Net Force:

m = 82 kg

d = 3 m

t = 0.55 s

Vf² = Vi² + 2ad

Vf² = 0 + 2(9.8 m/s²)(3 m) = 58.8 m²/s²

Vf = √58.8 m²/s² = 7.67 m/s

Use the Impulse Force equation:

FΔt = mΔv

F = (82 kg)(7.67 m/s) / (0.55 s) ≈ 1143 N

Therefore, the net force on the diver as he is brought to rest is approximately 1143 Newtons.