Biomechanics: Understanding the Stabilizing Component of the Brachialis Force

What is the magnitude of the stabilizing component of the brachialis force?

If the brachialis muscle produces 750 N of force and attaches to the forearm at an angle of 32 degrees, what is the magnitude of the stabilizing component of the brachialis force?

Answer:

The magnitude of the stabilizing component of the brachialis force is approximately 636 N.

From the question we are given that the brachialis muscle produces 750 N of force, attaches to the forearm at an angle of 32 degrees, and is located 0.35 m from the elbow. To calculate the magnitude of the stabilizing component of the brachialis force, we use the formula:

F_stabilizing = F_brachialis × cos(angle)

Plugging in the values:

F_stabilizing = 750 N × cos(32°)

F_stabilizing = 750 N × 0.84805 (cosine of 32° approximately)

F_stabilizing = 636.04 N

Therefore, the magnitude of the stabilizing component of the brachialis force is approximately 636 N. This value is calculated using the cosine of the given angle and the total force generated by the brachialis muscle.

← Interesting physics problem on coefficient of linear expansion Calculating the moment of inertia for alex s rolling hoop →