Calculate the p.d., power, and energy of a lamp

Potential Difference (p.d.) across the lamp:

The p.d. across the lamp is 1.0V.

The potential difference across the lamp can be calculated using Ohm's Law, which states that voltage (V) is equal to current (I) multiplied by resistance (R). In this case, the current passing through the lamp is 1.0A and the resistance of the lamp is 122 ohms. Therefore, the p.d. across the lamp is 1.0V.

Power of the lamp:

The power of the lamp is 1.0W.

The power of the lamp can be calculated using the formula P = IV, where P is power, I is current, and V is voltage. In this case, the current passing through the lamp is 1.0A and the p.d. across the lamp is 1.0V. Therefore, the power of the lamp is 1.0W.

Energy transferred to the lamp in 10 seconds:

The amount of energy transferred to the lamp in 10 seconds is 10 joules.

The amount of energy transferred to the lamp in 10 seconds can be calculated using the formula E = Pt, where E is energy, P is power, and t is time. In this case, the power of the lamp is 1.0W and the time is 10 seconds. Therefore, the amount of energy transferred to the lamp in 10 seconds is 10 joules.

← Differentiating between fuse wire and phase wire in electrical systems Alejandro s walking distance and velocity →