Calculating de Broglie Wavelength for Proton
What is the de Broglie wavelength for a proton with energy 50 keV?
Due to the limitations of Canvas, please give the wavelength in angstroms (x 10-10 m) to 2 sig figs.
Answer:
1.2826 x 10^-13 m
The de Broglie wavelength for a proton with energy 50 keV is calculated by using the formula:
λ = h / √(2mK)
Where λ is the de Broglie wavelength, h is the Planck's constant, m is the mass of the proton, and K is the kinetic energy.
Given:
K = 50 keV = 50 x 1.6 x 10^-16 J = 80 x 10^-16 J
m = 1.67 x 10^-27 kg
h = 6.63 x 10^-34 J s
Substitute the values into the formula:
λ = 6.63 x 10^-34 / √(2 x 1.67 x 10^-27 x 80 x 10^-16)
λ ≈ 1.2826 x 10^-13 m
Therefore, the de Broglie wavelength for a proton with energy 50 keV is approximately 1.2826 x 10^-13 meters, which is equivalent to 128.26 angstroms (x 10^-10 m) to 2 significant figures.