Calculating Kinetic Energy of a Person in an Elevator

03 Nov 2021

Question:

If an elevator is moving at a speed of 5 m/s and the person in it is 82 kg, what is the person’s kinetic energy?

The person's kinetic energy is 1025J.

Kinetic Energy Formula:

KE = 1/2 * m * v^2

Plugging in the given values:

KE = 1/2 * 82 * 5^2

KE = 1/2 * 82 * 25

KE = 41 * 25

KE = 1025J

Therefore, the kinetic energy of the person in the elevator moving at a speed of 5 m/s is 1025J.