Calculating kW Input to 100 HP AC Induction Motor

Question:

What is the kW input to a 100 nameplate HP AC induction motor with a load factor of 70% and an efficiency of 92.3%?

Answer:

The kW input to the 100 nameplate HP AC induction motor is 76.92 kW.

Explanation:

To calculate the kW input to the motor, we can use the following formula:

Input Power (kW) = (HP × Load Factor) / (η × 0.746)

Where:

HP = Horsepower = 100 HP

Load Factor = 70% = 0.70

η = Efficiency = 92.3% = 0.923

Substitute the given values into the formula:

Input Power (kW) = (100 HP × 0.70) / (0.923 × 0.746)

Input Power (kW) = (70) / (0.688858)

Input Power (kW) ≈ 76.92 kW

Therefore, the kW input to the motor is approximately 76.92 kW.

In this calculation, we converted the efficiency and load factor from percentages to decimal values. Then, we used the formula for input power considering the horsepower, load factor, and efficiency. After substituting the given values, we calculated the kW input to the motor to be approximately 76.92 kW.

← Calculating the resistivity of a wire Finding the bright side understanding electron and conventional current →

More Posts: