Calculating Work Done to Move a Proton Between Charged Plates

How much work is done to move a proton from the negative plate to the positive plate?

A. 7.40 × 10^-18 J

B. 46.2 J

C. 1.69 × 10^-14 J

D. -7.40 × 10^-18 J

Final Answer:

To move a proton between charged plates, we calculate the work done using the electric potential difference between the plates and the charge of the proton. The work done is approximately 7.40 × 10^-18 J.

When moving a proton between two charged parallel plates that are 2.1 cm apart with an electric field of 2200 N/C, we can determine the work done by considering the electric potential difference and the charge of the proton.

To calculate the work done, we first find the electric potential (V) between the plates by multiplying the electric field (E) by the distance (d) between the plates. In this case:

V = E * d

V = 2200 N/C * 0.021 m

V = 46.2 V

Next, we calculate the work done (W) using the charge of the proton (q) and the electric potential (V) we just calculated:

W = q * V

Charge of the proton (q) ≈ 1.6 × 10^-19 C

W ≈ 1.6 × 10^-19 C * 46.2 V

W ≈ 7.40 × 10^-18 J

Therefore, the work done to move a proton from the negative plate to the positive plate is approximately 7.40 × 10^-18 J. This calculation involves considering the electric potential difference and the charge of the proton in the given scenario.