Car Acceleration: Journey to 6.6m/s
How far does a car travel when accelerating uniformly to a speed of 6.6m/s?
Given the car accelerates from rest to a speed of 6.6m/s in 6.5 seconds, find the distance the car travels during this time.
Answer:
The car travels a distance of 21.45 meters during this time.
When a car accelerates uniformly from rest to a speed of 6.6m/s in 6.5 seconds, it covers a distance of 21.45 meters. This journey showcases the principle of kinematic equations, where the initial velocity, time, and acceleration are key factors in determining the distance traveled.
To calculate the distance the car travels during this acceleration, we utilize the kinematic equation for displacement:
s = ut + 0.5at²
Where:
- s represents the distance
- u is the initial velocity
- t signifies the time taken
- a denotes the acceleration
Given that the initial velocity u is 0 m/s, the time t is 6.5 seconds, and the acceleration a is 6.6 m/s², substituting these values into the equation yields:
s = 0 + 0.5(6.6)(6.5) = 21.45 meters
Therefore, the car journeys a distance of 21.45 meters in the process of accelerating to a speed of 6.6m/s. This showcases the dynamic nature of motion and the ability to quantify such movements using fundamental kinematic principles.