Ice Formation: Mass and Volume Calculation

What is the process to calculate the mass and volume of ice when water is cooled to form ice at -10°C? To calculate the mass and volume of ice when water is cooled to form ice at -10°C, we need to use the formula: Mass = Density × Volume. Given the densities of water and ice, along with the initial volume of water, we can determine the mass and volume of the ice.

Understanding the Calculation Process

Firstly, we calculate the mass of the water by multiplying the density of water (0.997 g/ml) with the initial volume of water (525 ml):

Mass of water = 0.997 g/ml × 525 ml = 522.375 g

After the water is cooled to form ice at -10°C, we assume that the volume of ice remains the same as the volume of water. Using the density of ice (0.917 g/ml), we then calculate the mass and volume of the ice:

Mass of ice = 0.917 g/ml × 525 ml = 481.425 g

Volume of ice = 525 ml

Therefore, the final answers are as follows:

The mass of the ice is 481.425 g and the volume of the ice is 525 ml.

By understanding the formula and utilizing the given densities and volumes, we can accurately calculate the mass and volume of ice formed when water is cooled to -10°C. This process allows for a precise determination of the characteristics of the ice produced.

← Conglomerate sandstone siltstone particle size comparison in sedimentary rocks College baseball player comparing wooden and metal bats calculating ball acceleration →

More Posts: