Ice-skating Clown and Fake Barbell Performance

What is the mass of the barbell thrown away by the ice-skating clown?

a) 10.0 kg

b) 4.00 kg

How much force is exerted to the barbell by the clown when thrown?

a) 80 N

b) 100 N

Answer:

The mass of the barbell thrown away by the ice-skating clown is indeed 4.00 kg.

The force exerted to the barbell by the clown when thrown is 100 N.

During an ice-skating performance, an initially motionless 80.0-kg clown throws a fake barbell away. The clown's ice skates allow her to recoil without friction, resulting in the barbell being thrown with a velocity of 10.0 m/s and the clown recoiling with a velocity of 0.500 m/s.

Mass of the Barbell:

To determine the mass of the barbell, we can use the principle of conservation of momentum. Initially, the system consisting of the clown and the barbell has zero momentum since the clown is motionless.

Using the equation for momentum: Initial momentum = Final momentum

0 kg * 0 m/s + 80 kg * 0.500 m/s = m * 10 kg * 10.0 m/s

After simplifying, we find that the mass of the barbell is indeed 4.00 kg.

Force Exerted to the Barbell:

To determine the force exerted on the barbell by the clown, Newton's second law can be applied, which states that force is equal to mass times acceleration.

Thus, the force exerted can be calculated using the formula: Force = mass * (change in velocity / time taken)

After applying the values: Force = 4.00 kg * ((10.0 m/s - 0.0 m/s) / 0.40 s)

By simplifying, it is determined that the force exerted on the barbell by the clown is 100 N.