Magnitude of the emf induced between the two sides of a scalloped hammerhead shark's head
What is the magnitude of the induced emf between the two sides of the shark's head?
A scalloped hammerhead shark swims at a steady speed of 1.5m/s with its 90cm-wide head perpendicular to the earth's magnetic field of 53 A/m. What is the magnitude of the induced emf between the two sides of the shark's head?
Magnitude of the induced emf
The magnitude of the emf induced between the two sides of the shark's head is 71.55 V (rounded to two significant figures).
When a scalloped hammerhead shark swims at a steady speed with its head perpendicular to the earth's magnetic field, an emf is induced between the two sides of its head. This emf can be calculated using the formula: emf = B * L * v, where B is the magnetic field strength, L is the length of the conductor (in this case, the width of the shark's head), and v is the velocity of the conductor (shark's speed).
Given values:
B = 53 A/m
L = 0.9 m
v = 1.5 m/s
Plugging the values into the formula:
emf = (53 A/m) * (0.9 m) * (1.5 m/s) = 71.55 V
Therefore, the magnitude of the emf induced between the two sides of the shark's head is 71.55 V.