Projectile Motion: A Interactive Study

How can we calculate the velocity of the first ball as it strikes the ground and the velocity of the second ball as it strikes the ground? What is the difference in the time the balls spend in the air? And how far apart are the balls 0.611 seconds after they are thrown? The velocity of the first ball as it strikes the ground is 13.7 m/s downward, while the velocity of the second ball as it strikes the ground is 13.7 m/s upward. The first ball spends more time in the air compared to the second ball. Both balls are at the same horizontal position 0.611 seconds after they are thrown.

Given that two students are on a balcony 21.8 m above the street and one throws a ball vertically downward at 13.7 m/s while the other throws a ball vertically upward at the same speed, we can determine the following:

a) Velocity of the first ball:

The velocity of the first ball as it strikes the ground is 13.7 m/s, vertically downward.

b) Velocity of the second ball:

The velocity of the second ball as it strikes the ground is also 13.7 m/s, but in the opposite direction (vertically upward).

c) Difference in time in air:

The difference in the time the balls spend in the air can be calculated by comparing their vertical motions. Since both balls have the same initial upward velocity and the second ball just misses the balcony on the way down, the first ball spends more time in the air.

d) Distance between the balls:

The distance between the balls 0.611 seconds after they are thrown can be calculated by multiplying the time by the average horizontal velocity, which is zero in this case. Therefore, both balls are at the same horizontal position at that moment.

For a deeper understanding of Projectile Motion and how it relates to the scenario described above, explore more resources to enhance your knowledge on the topic!

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