Speed of a Stone Before Touching the Ground
What is the speed of a stone before touching the ground?
Choose the correct answer:
(a) 5.6 m/s
(b) 1.6 m/s
(c) 9.6 m/s
(d) 3 m/s
(e) none of these
Answer:
The speed of the stone before touching the ground is approximately 5.6 m/s.
To find the speed of the stone before touching the ground, we can use the equation v² = u² + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance traveled.
In this case, the stone is dropped, so the initial velocity is 0 m/s, the acceleration is the acceleration due to gravity (approximately 9.8 m/s²), and the distance traveled is the height of the building (1.6 meters).
Plugging in the values, we get:
v² = 0² + 2(9.8)(1.6)
v² = 31.36
v = √31.36
v ≈ 5.6 m/s
Therefore, the speed of the stone before touching the ground is approximately 5.6 m/s.