The Exciting Physics of Movie Stunt Cars!

How far does a movie stunt car driven off a cliff travel during its fall?

Ignoring air resistance, a movie stunt car is driven off a cliff of 44.1 m-high with a horizontal speed of 10.0 m/s. How far does the car travel during its fall?

Final answer: The stunt car, driven off a cliff with a horizontal speed, covers a horizontal distance of 30 m while falling from the height of 44.1m, considering the gravitational constant is 9.8 m/s².

Explanation: The subject of your question is Physics, specifically the concepts of Projectile Motion and Gravitational Acceleration. The car in the question travels horizontally with a constant speed while falling vertically under the gravity. The horizontal distance the car covers while falling is determined by the horizontal speed and the time it takes to hit the ground.

Time can be solved by using the equation t= sqrt(2h/g), where h is the height of the cliff and g is the gravitational constant. Substituting in the given values for h(44.1 m) and g(9.8 m/s²), we get t approx 3.0 seconds.

The horizontal distance the stunt car travels is then (10 m/s) * (3.0 s) = 30 m. So, the answer is b. 30 m.