Title: Reflecting on the Maximum Extension and Retraction Forces of a Cylinder

What are the maximum extension and retraction forces for a cylinder with specific bore and rod diameters in a system with a maximum pressure of 1500 psi?

Given a cylinder with a bore diameter of 5" and a rod diameter of 2.5", how can we calculate the maximum extension and retraction forces?

Maximum Extension and Retraction Forces Calculation

The maximum extension force for the cylinder is calculated as 29445 lb, while the maximum retraction force is calculated as 23850 lb.

Reflecting on the data provided, we can see that the calculation of the maximum extension and retraction forces for a cylinder involves understanding the bore and rod diameters, as well as the maximum pressure of the system. In this case, the bore diameter is 5" and the rod diameter is 2.5", with a maximum pressure of 1500 psi.

To calculate the maximum extension force, we use the formula F = P*A, where F is the force, P is the pressure, and A is the area. For extension, the cylinder acts on the total bore area, which is calculated as A = π*(D/2)², where D is the bore diameter. Substituting the values, we get A = π*(5"/2)² = 19.63 in². Therefore, the maximum extension force F is 1500 psi * 19.63 in² = 29445 lb.

For retraction, the rod occupies part of the bore area, so the effective bore area is calculated as A' = A - π*(d/2)², where d is the rod diameter. Substituting the values, we get A' = 19.63 in² - π*(2.5"/2)² = 15.9 in². The maximum retraction force F' is then calculated as 1500 psi * 15.9 in² = 23850 lb.

Therefore, based on the given data and calculations, the maximum extension force for the cylinder is 29445 lb, while the maximum retraction force is 23850 lb under the specified maximum pressure of 1500 psi.