Final Speed of Billiard Ball A After Collision
What is the final speed of Billiard Ball A after the collision?
The final speed of Ball A after the collision is 6.8 m/s. According to the conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. After the collision, Ball B is moving in the opposite direction with a velocity of 6.8 m/s. The final momentum of Ball B can be calculated as: Final momentum of Ball B = mass of Ball B * final velocity of Ball B = 3.9 kg * (-6.8 m/s) [since it is moving in the opposite direction] = -26.52 kg·m/s The final momentum of Ball A can be calculated using the conservation of momentum: Total initial momentum = Total final momentum (0 kg·m/s) + (68.25 kg·m/s) = (final momentum of Ball A) + (-26.52 kg·m/s) Simplifying the equation, we find: final momentum of Ball A = 26.52 kg·m/s To calculate the final velocity of Ball A, we divide the final momentum by the mass of Ball A: final velocity of Ball A = final momentum of Ball A / mass of Ball A = 26.52 kg·m/s / 3.9 kg = 6.8 m/s Therefore, the final speed of Ball A after the collision is 6.8 m/s.